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Measurement, time & conversions · Topic 13 of 15

Temperature: Fahrenheit ↔ Celsius

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Math · temperature

Temperature: Fahrenheit ↔ Celsius

°F = 9/5 °C + 32 and °C = 5/9 (°F − 32); anchor answers to 0/32, 37/98.6 and 100/212.

01 · °C → °F°F = 9/5 × °C + 32
02 · °F → °C°C = 5/9 × (°F − 32)
03 · MemorizeBody temp 37 °C = 98.6 °F
01

The rules

°F → °C: do the subtraction in parentheses first
°C → °F: multiply first, add 32 last
02

Know by heart

°C → °F: multiply by 9/5, then add 32 must know
°F → °C: subtract 32, then multiply by 5/9 must know
Water freezes at 0 °C = 32 °F and boils at 100 °C = 212 °F must know
Normal body temperature: 37 °C = 98.6 °F must know
9/5 = 1.8: °F = 1.8 °C + 32; °C = (°F − 32) ÷ 1.8
03

Worked examples

39 °C: 1.8 × 39 = 70.2; 70.2 + 32 = 102.2 °F
77 °F: 77 − 32 = 45; 5/9 × 45 = 25 °C
101.3 °F: 101.3 − 32 = 69.3; 5/9 × 69.3 = 38.5 °C
04

°C → °F or °F → °C?

Commonly confused
Celsius → FahrenheitFahrenheit → Celsius
Formula°F = 9/5 × °C + 32°C = 5/9 × (°F − 32)
Order of stepsMultiply, then add 32Subtract 32, then multiply
Fraction9/5 (= 1.8)5/9
Example39 °C = 102.2 °F77 °F = 25 °C
05

Common mistakes

Subtract 32 before multiplying: 212 °F = 100 °C, not 85.8 °C
Don't swap 9/5 and 5/9 — above freezing, °F is the bigger number
06

More detail

Show 3 more facts
1 Celsius degree = 1.8 Fahrenheit degrees (100 C° span = 180 F°)
−40 °C = −40 °F (the one point where the scales meet)
Kelvin (water freezes at 273.15 K) is a Chemistry topic
Pearl

To Fahrenheit, add 32 last; to Celsius, take 32 away first.

Sources · OpenStax Prealgebra 2e §7.5 Systems of Measurement (Fahrenheit and Celsius) · OpenStax College Physics 2e §13.1 Temperature · Union Test Prep — HESI A2 Mathematics study guide, p. 5: Temperature · CCRI Tutoring Center — HESI Math (Celsius/Fahrenheit among the topics) · Built from the verified NurseSavvy HESI A2 fact map (facts reviewed 2026-10-16). HESI is a trademark of Elsevier; NurseSavvy is not affiliated with Elsevier.

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HESI and HESI A2 are registered trademarks of Elsevier. NurseSavvy is not affiliated with or endorsed by Elsevier.